Posted by Justine on Monday, March 12, 2012 at 10:16pm.
Let the rate of the input source be x cm^3 per minute
So the effective dV/dt = (x- 700) cm^3/min
let the height of the water level be h cm
let the radius of the water level be r cm
h/r = 10/1.75
10r = 1.75h
r = .175 h
V = (1/3)π r^2 h
= (1/3)π(.030625h^2)(h)
= .010208333πh^3
dV/dt = .030625πh^2 dh/dt
x - 700 = .030625π(4.5)^2 (26)
x = 750.655 cm^3/min
check my arithmetic.
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