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March 29, 2015

March 29, 2015

Posted by **Justine** on Monday, March 12, 2012 at 10:16pm.

- math - calculus -
**Reiny**, Monday, March 12, 2012 at 11:00pmLet the height of water be h ft

Volume of water = π(3^2)h = 9πh

dV/dt = 18π dh/dt

9/(18π) = dh/dt

dh/dt = 1/(2π) , a constant no matter what the height is

- math - calculus -
**Tom**, Tuesday, March 13, 2012 at 7:21pmThe above answer is incorrect..

everything is right except v=9pi(h)

differentiate both sides. gives you...

dv/dt=9pi dh/dt

9/9pi= dh/dt.

dh/dt= 1/pi

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