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January 22, 2017
Posted by **Claries** on Monday, March 12, 2012 at 10:02pm.

- Math:Trig.!!!! -
**Steve**, Tuesday, March 13, 2012 at 4:37amat the beginning, till some time a,

h(t) = 200 - 16t^2

due to free-fall. When h(t) reaches 200 - max cord extension, the springy characteristics of the cord enter in. If the cord could rebound 100%, the wave would have a constant amplitude.

for t>a,

h(t) = b - c*cos(k(t-a))

which allows for an offset cosine wave, starting at its minimum.

However, the amplitude dampens exponentially, so the curve for t>a would more likely be something like

h(t) = b - c*cos(k1(t-a))*e^(-k2*(t-a))

So, a parabola to start with, then a damped cosine wave.