Al(s) + H2SO4(aq)-> Al2(SO4)3(aq) + H2(g)
Consider the unbalanced equation above. What volume of 0.490 M H2SO4 is needed to react with excess aluminum to produce 1.60 g of Al2(SO4)3? Use a molar mass with at least as many significant figures as the data given.
chemistry - DrBob222, Monday, March 12, 2012 at 9:50pm
1. Balance the equation.
2. How many moles Al2(SO4)3 do you need? mols = g/molar mass.
3. Use the equation, convert mols Al2(SO4)3 to mols H2SO4.
4. M H2SO4 = moles/L
You know M and mols, solve for L.