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Al(s) + H2SO4(aq)-> Al2(SO4)3(aq) + H2(g)

Consider the unbalanced equation above. What volume of 0.490 M H2SO4 is needed to react with excess aluminum to produce 1.60 g of Al2(SO4)3? Use a molar mass with at least as many significant figures as the data given.

  • chemistry - ,

    1. Balance the equation.
    2. How many moles Al2(SO4)3 do you need? mols = g/molar mass.
    3. Use the equation, convert mols Al2(SO4)3 to mols H2SO4.
    4. M H2SO4 = moles/L
    You know M and mols, solve for L.

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