Using this data,
2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3
NO2(g) == NO(g) + ½ O2(g) Kc = 3.93
calculate a value for Kc for the reaction,
NOCl (g) + ½ O2 (g) == NO2 (g) + ½ Cl2 (g)
A. 20.2
B. 2.06 X 10-4
C. 4.49
D. 4.84 X 10-3
E. 0.223
eliminated down to b or d
but going with b unless wrong
chemistry - DrBob222, Monday, March 12, 2012 at 6:46pm
I disagree with b AND d.
Use equation 1, take 1/2 of it, and reverse it. K1 for that will be 1/sqrt Kc.
Multiply k1 by equation 2 reversed so k2 = 1/Kc
Then k1*k2 = ?
Check my manipulations to be sure you get the equation in the problem.
chemistry - bob, Monday, March 12, 2012 at 9:03pm
when you reverse it do you get a negative?
-3.20x10-3/2=-1.6x10-3
1/.04=25
1/3.93=.254
25x.245
=6.125
not an answer choice?
To calculate the value of Kc for the reaction, you have to use the given equilibrium constants and manipulate the equations accordingly.
First, take equation 1 and reverse it, as well as taking half of it. This means the equation becomes:
½ Cl2(g) + NO(g) == NOCl(g)
The equilibrium constant for this new equation, K1, can be found by taking the reciprocal of the square root of the original equilibrium constant Kc for equation 1. Therefore:
K1 = 1/sqrt(Kc) = 1/sqrt(3.20 x 10^-3) = 1/0.0566 = 17.65
Next, take equation 2 and take its reciprocal to get the equilibrium constant for the reversed equation, K2. Therefore:
K2 = 1/Kc = 1/3.93 = 0.254
Finally, multiply K1 and K2 together to obtain the new equilibrium constant Kc for the given reaction:
Kc = K1 x K2 = 17.65 x 0.254 = 4.48
Therefore, the value for Kc is approximately 4.48. Comparing this value to the given answer choices, it aligns with answer choice C, 4.49.
To calculate the value of Kc for the reaction:
1. Start with equation 1 and reverse it by dividing the given Kc value by 2:
2 NOCl(g) + ½ O2(g) ↔ NO(g) + ½ Cl2(g) (K1 = 1/sqrt(Kc) = 1/sqrt(3.20x10-3) = 55.9)
2. Reverse equation 2 to obtain the inverse of the given Kc value:
NO(g) + ½ O2(g) ↔ NO2(g) (K2 = 1/Kc = 1/3.93 = 0.254)
3. Multiply K1 and K2 to get the final value of Kc for the reaction:
K1 * K2 = 55.9 * 0.254 = 14.191
The correct answer is not given in the options provided.