# Calculus (Definite Integrals - Work)

posted by
**Mishaka** on
.

Recall that work is defined to be force times distance, and that the weight (force) of a liquid is equal to its volume times its density. A fish tank has a rectangular base of width 2 feet and length 6 feet and sides of height 5 feet. If the tank is filled with water weighing 62.5 lb per cubic foot, the work required to pump all the water just over the top of the tank is:

A.) 781.24 ft-lb

B.) 150.0 ft-lb

C.) 9375.o ft-lb

D.) 3750.0 ft-lb

E.) 865.0 ft-lb