Posted by Jill on Monday, March 12, 2012 at 3:30pm.
The first one is a circle centred at (2,-1), or
(x-2)^2+(y+1)^2=20+4+1=25
or
C: (x-2)^2+(y+1)^2=5^2
The second equation is a straight line.
L: 4x+3y=5
To solve the system, set
y=(5-4x)/3
and substitute into equation C
or
(x-2)^2+((5-4x)/3+1)^2=25
Solve for x to get x=5 or x=-1
Substitute into y=(5-4x)/3
to get
y=-5, y=3
So the intersections are
(5,-5), or (-1,3)
Related Questions
math - Solve the system x^2+y^2-4x+2y=20 4x +3y =5
Math - Solve each system of equations using substitution. 1.) x+3y=-4 y+x=0 2.) ...
math - A linear system may have a unique solution, no solution, or infinitely ...
algebra - use substitution to solve the linear system 3x+2y=-5 4x-3y=16 help plz...
math - what would x^2+y^2-4x+2y=0 (Equation for a cirlce) be in r^2=(x-h)^2(y-k...
Algerbra1 - Use elimination to solve each system of equations: s-t=4 over s+t=2...
math - PLEASE!!!!i need help on these 4: *4y=15-3x 2y=3x+21 *4x=5y-14 y=-6x-9 *...
math - PLEASE!!!!i need help on these 4: *4y=15-3x 2y=3x+21 *4x=5y-14 y=-6x-9 *...
Algebra 1 - Which of the following is parallel to the line: 4x+2y=-3? a) 4x+3=2y...
Algebra - Solve the system of equations: First:4x-2y=2 Second:y=-4x-7 4x-2(-4x-7...
For Further Reading
