Posted by Constance shapela on Monday, March 12, 2012 at 6:50am.
Since the stick is 100 cm long, one string (with tension T1) is attached 30 cm from the center and the other (T2) is 20 cm away, on the other side of center.
For a balance of the torque about the center, the string closest to center must have 1.5 times as much tension as the other. Total tension for both is
T1 + T2 = M*g = 1.96 N
Since T2 = 1.5*T1 ,
2.5 T1 = 1.96 N
T1 = 0.784 N
T2 = 1.176 N
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