Physics
posted by Melissa .
A student throws a baseball vertically upward, and 2.8s later catches it at the same level. Neglecting air resistance , calculate the following
(a) the velocity at which the ball left the students hand
(b) the height to which the ball climbed above the students hand

(a) The baseball reached maximum height and zero velocity after t = 1.4 seconds, half the total interval. The initial velocity was Vo = g*t = 13.72 m/s
(b) The height reached is
H = (1/2) Vo t = Vo^2/(2g)