Monday

March 2, 2015

March 2, 2015

Posted by **Anonymous** on Sunday, March 11, 2012 at 11:42pm.

[1+sinx]/[1+cscx]=tanx/secx

=[1+sinx]/[1+1/sinx]

=[1+sinx]/[(sinx+1)/sinx]

=[1+sinx]*[sinx/(sinx+1)]

=[sinx+sin^2x]/[sinx+1]

=[sinx+(1-cos^2x)]/[sinx+1]

=???

This is where I'm stuck. Can someone help me. Please check what I got is right so far it's possible that I made a mistake somewhere.

Please and Thank you

- Trig Help -
**Reiny**, Sunday, March 11, 2012 at 11:59pmLS = (1 + sinx)/(1 + 1/sinx)

= (1 + sinx)/( ( sinx + 1)/sinx )

= (1 + sinx) ( sinx/(1+sinx))

= sinx

RS = (sinx/cosx)(cosx)

= sinx

= LS

- Trig Help -
**Anonymous**, Monday, March 12, 2012 at 12:46amso I have to do both sides but I thought can only do one side

- math 156Trig Help -
**sara**, Wednesday, July 11, 2012 at 11:33am2x

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