Homework Help: Trig Help

Posted by Anonymous on Sunday, March 11, 2012 at 11:42pm.

Prove the following:
[1+sinx]/[1+cscx]=tanx/secx
=[1+sinx]/[1+1/sinx]
=[1+sinx]/[(sinx+1)/sinx]
=[1+sinx]*[sinx/(sinx+1)]
=[sinx+sin^2x]/[sinx+1]
=[sinx+(1-cos^2x)]/[sinx+1]
=???

This is where I'm stuck. Can someone help me. Please check what I got is right so far it's possible that I made a mistake somewhere.

Please and Thank you

Trig Help - Reiny, Sunday, March 11, 2012 at 11:59pm
LS = (1 + sinx)/(1 + 1/sinx)
= (1 + sinx)/( ( sinx + 1)/sinx )
= (1 + sinx) ( sinx/(1+sinx))
= sinx

RS = (sinx/cosx)(cosx)
= sinx
= LS
Trig Help - Anonymous, Monday, March 12, 2012 at 12:46am
so I have to do both sides but I thought can only do one side
math 156Trig Help - sara, Wednesday, July 11, 2012 at 11:33am
2x

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