# Trig Help

posted by
**Anonymous** on
.

Prove the following:

[1+sinx]/[1+cscx]=tanx/secx

=[1+sinx]/[1+1/sinx]

=[1+sinx]/[(sinx+1)/sinx]

=[1+sinx]*[sinx/(sinx+1)]

=[sinx+sin^2x]/[sinx+1]

=[sinx+(1-cos^2x)]/[sinx+1]

=???

This is where I'm stuck. Can someone help me. Please check what I got is right so far it's possible that I made a mistake somewhere.

Please and Thank you