Posted by alice on Sunday, March 11, 2012 at 10:08pm.
2(3y-4)^(3/5) = 54
(3y-4)^(3/5) = 27
3y - 4 = 27^(5/3)
3y = 27^(5/3) + 4
y = (27^(5/3) + 4)/3
= (243 + 4)/3 = 247/3 or 82 1/3
1-(1/a)/1-(1/a^2)
multiply top and bottom by a^2 to get
(a^2-a)/(a^2-1)
= a(a-1)/(a+1)(a-1)
= a/(a+1)
or, since you seem to like reciprocals so much,
1 /(1+1/a)
:-)
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