Posted by Anonymous on Sunday, March 11, 2012 at 6:59pm.
#1 I believe is just the pH of the salt acting as an acid.
..............HX^- ==> H^+ + X^2-
initial.......0.1......0......0
change........-x.......x.......x
equil.......0.1-x......x.......x
Set up k1 and solve for x. You will not be able to solve without using a quadratic equation.
4). This one looks amazingly like NaHCO3 for which (H^+) = sqrt(k1k2)
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