ln [2.30E-2] = ln(0.102) - (k s-1)(2360 s)
k = 6.31E-4 s -1
I did 2360k = 1n(0.102 * 0.023)
2360k = -6.055
then I divided 2360 by -6.055 but I didn't get 6.31e-4. Where did I mess up???
ln(.023)=ln(.102)-2360k
2360k=ln(.102)-ln(.023)=ln(.102/.023)
k= about 1.49/2360=6.31E-4
Thank you!!!
To understand where you went wrong, let's break down the steps you took:
Step 1: You started with the equation ln([2.30E-2]) = ln(0.102) - (k s-1)(2360 s).
Step 2: You substituted the given value of k = 6.31E-4 s-1 into the equation.
Step 3: You multiplied 2360 and k, which should equate to -6.055.
Step 4: You divided 2360 by -6.055, expecting to get 6.31E-4.
However, this is where the mistake occurred. Dividing 2360 by -6.055 will not give you the value of k. Instead, it will provide the ratio between the two numbers.
To find the value of k, you need to isolate it on one side of the equation. Here's the correct method:
Step 1: Start with the equation 2360k = ln(0.102 * 0.023).
Step 2: Calculate the natural logarithm of the product (0.102 * 0.023) as ln(0.002346).
Step 3: Then, divide both sides of the equation by 2360: k = ln(0.002346) / 2360.
By performing this calculation, you will obtain the actual value of k, which is approximately 1.5138E-6 s-1.