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September 16, 2014

September 16, 2014

Posted by **TOTALLY lost** on Sunday, March 11, 2012 at 11:04am.

Find the variation constant in which y varies inversely as x, and the following condition exists.

Y=30 when x = 1/6

k will = ____.

============================

The strength S of a rectangle beam varies jointly as its width w and the square of its thickness t.

If a wood beam 6 inches wide and 5 inches thick supports 500 pounds, how much can a similar beam 6 inches wide and 3 inches thick support? Round to the nearest pound if needed.

Thank you ahead of time for any consideration .

- Lost in the pits of ALG -
**Steve**, Sunday, March 11, 2012 at 1:28pmsince y varies inversely as x, xy=k, a constant

1/6 * 30 = k

5 = k

-------------------------

S(w,t) = kwt^2

500 = k*6*25

500 = 150k

k=4

So, now we know k, and we can figure S from any w and t:

S(6,3) = 4*6*9 = 216

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