Question

given the circle x^2+y^2+2x-2y-14=0, find it's intersection with the y-axis. please help me....

Answer 1

The y-axis is the line x=0.

Thus substitute x=0 in the given equation and solve for y:
x^2+y^2+2x-2y-14=0, substitute x=0
0+y²+0-2y-14=0
y²-2y-14=0
The resulting quadratic equation can be solved using the quadratic formula.
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