Posted by **TOTALLY lost** on Sunday, March 11, 2012 at 5:58am.

The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 9 amperes when the resistance is 940 ohms. What is the current when the resistance is 580 ohms?

Thank you yet again. Almost through with this part of the class thank goodness!

- ALG WORD PROBLEM -
**Damon**, Sunday, March 11, 2012 at 6:23am
i = k/r

9 = k/940

k = 8460

i = 8460/r

i = 8460/580

i = 14.6 amps

by the way, k is the voltage V

- ALG WORD PROBLEM -
**Henry**, Wednesday, December 23, 2015 at 9:30pm
E = I*R = 9 * 940 = 8460 V. = Supply voltage.

I =E/R = 8460/580 = 14.6 Amps.

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