Posted by TOTALLY lost on Sunday, March 11, 2012 at 5:58am.
The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 9 amperes when the resistance is 940 ohms. What is the current when the resistance is 580 ohms?
Thank you yet again. Almost through with this part of the class thank goodness!

ALG WORD PROBLEM  Damon, Sunday, March 11, 2012 at 6:23am
i = k/r
9 = k/940
k = 8460
i = 8460/r
i = 8460/580
i = 14.6 amps
by the way, k is the voltage V

ALG WORD PROBLEM  Henry, Wednesday, December 23, 2015 at 9:30pm
E = I*R = 9 * 940 = 8460 V. = Supply voltage.
I =E/R = 8460/580 = 14.6 Amps.
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