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October 1, 2014

October 1, 2014

Posted by **Kaleen** on Saturday, March 10, 2012 at 9:17pm.

cos(t + 2πk) = cos t or sin(t + 2πk) = sin t

to evaluate each expression. (Enter your answers in exact form.)

(a)

sin(19π/4)

(b)

sin(−19π/4)

(c)

cos(11π)

(d)

cos(53π/4)

(e)

tan(−3π/4)

(f)

cos(π/4)

(g)

sec(π/6+ 2π)

(h)

csc(2π − 2π/3)

- Precalculus -
**Reiny**, Saturday, March 10, 2012 at 11:18pmhere is how I do these ....

(perhaps you might find it easier in degrees, 19π/4 radians = 855°

sin(19π/4) = sin 855°

take away 2 rotations, (720° or 4π)

sin 19π/4 = sin 3π/4 = sin 135°

3π/4 or 135° is in quadrant II and π/4 or 45° from the x-axis

We also know that in II, the sine is positive

so sin 3π/4 = sin π/4 = sin 45° = 1/√2 or √2/2

.....

d) cos(53π/4) or cos 2385°

take away 12π or 2160°

cos 53π/4 = cos 5π/4 or cos 225°

This angle is in quad III making it negative and 45 from the x-axis

cos 53π/4 = - cos π/4 = -1/√2 or -√2/2

do the others the same way.

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