posted by fernatesfsdf .
Calculate the solubility of Mn(OH)2 in GRAMS PER LITER when buffered at each of the following.
c) pH 11.5
Let x = solubility Mn(OH)2
Mn(OH)2 ==> Mn^2+ + 2OH^-
If pH = 7.4. Convert to pH, then to OH^-
Subsitute OH into Ksp for Mn(OH)2 and solve for Mn. That will be x and it will be in M or moles/L. Then convert to grams.
b and c are done the same way.
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