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October 31, 2014

October 31, 2014

Posted by **Susan** on Saturday, March 10, 2012 at 3:21pm.

A. What scores separate the middle 25% from the rest

b. What proportion would be expected to score between 45 and 55

c. What proportion would be expected to score 68 and above

- statistics -
**PsyDAG**, Sunday, March 11, 2012 at 12:01pmZ = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions and their related Z scores.

A. Find the Z score with .125 between score and mean. Insert ąZ value in the above equation and solve for the scores.

B and C. Solve for Z scores and use the table.

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