Posted by **Brian** on Saturday, March 10, 2012 at 2:40pm.

A projectile is launched from a platform 20 feet high with an initial velocity of 72 feet per second,

The height h of the projectile at t seconds after launch is given by h = –16t2 + 72t + 20 feet.

(a) How many seconds after launch does the projectile attain maximum height? Show work.

(b) What is the maximum height? Show work.

## Answer This Question

## Related Questions

- precalc - A projectile is launched from a platform 10 feet high with an initial ...
- precalc - A projectile is launched from a platform 20 feet high with an initial ...
- math - If a projectile is launched from a platform 30 feet high with an initial ...
- calculus - The height of a projectile launched into the air is given by h (t)= -...
- Algebra - The function H(t) = -16t2 + vt + s shows the height H (t), in feet, of...
- intermediate algebra - A projectile is launched directly upward from the top of ...
- algebra - The height in feet of a projectile with an initial velocity of 32 feet...
- algebra - The height in feet of a projectile with an initial velocity of 96 feet...
- algebra - A model rocket is launched upward with an initial velocity of 200 feet...
- Algebra - The height in feet of a projectile with an initial velocity of 32 feet...

More Related Questions