An asteriod is found a distance from the sun equal to 32 units times the earth's distance. What will be the length of time in years required for this asteriod to make one revolution around the sun?
An asteriod is found a distance from the sun equal to 32 units times the earth's distance. What will be the length of time in years required for this asteroid to make one revolution around the sun?
Rast = 32 x 92,960,242 = 2,974,727,744 miles
GMsun = gravitational constant of sun = 4.68772x10^21ft^3/sec^2
Vo = sqrt[GMsun/Rast] = orbital velocity
=sqrt[4.68772x10^21/2,974,727,744(5280)]
=17,275.88fps.
T = 2(Pi)R/V
2(2,974,727,744)5280(3.14)/17275.88 =
= 5,712,418,683sec = 181 years
Alternatively"
T = 2(Pi)sqrt[R^3/GMsun]
= 2(3.14)sqrt[(2974727744(5280))^3/4.68772x10^21] = 5,712,418,683sec. = 181 years.