Posted by Martin on Saturday, March 10, 2012 at 12:37am.
solve the system
7x^2  5y^2 + 20y = 3
21x^2 + 5y^2 =209

math  Steve, Saturday, March 10, 2012 at 5:57am
since 7x^2 = 5y^2  20y + 3
21x^2 = 15y^2  60y + 9
plug that into the 2nd equation to get
20y^2  60y  200 = 0
y^2  3y  10 = 0
(y5)(y+2) = 0
From there you can see that the circle and the hyperbola intersect at
(3,2) (3,2) (2,5) (2,5)
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