Posted by Sarah on Friday, March 9, 2012 at 8:06pm.
M PCl5 = 0.463 mols/4.80L = 0.09646 which is more places than allowed but I like to keep one extra place, go through the calculations and round in the last step.
..........PCl5 ==>PCl3 + Cl2
initial.0.09646......0......0
change...-x.........x.......x
equil..0.09646-x.....x......x
Kc = 1.80 = (PCl3)(Cl2)/(PCl5)
Substitute from the ICE chart into the Kc expression and solve for x, then for 0.09646
What answers did u get for PCl5 and PCl3...I want to verify them please.
I didn't work it. Give me your answers and I will check it.
I got x=0.091766....now what do i do? I'm confused. Also can check if this is right for x?
I obtained 0.0918M for x and that is (PCl3). The problem also asked for (PCl5) and that is 0.09646-x = ? and round to 3 s.f. I obtained 0.00466 for that.
yes it is correct! thank you :) I really appreciate it!
How do you solve for x with the equation 1.8 = x^2 / .0964 - x? i dont understand what to do isolate x
Related Questions
Chemistry - a 1.00-mol sample of phosphorus pentachloride placed in 10.0-L ...
chem - A sample of PCl5 weighing 2.69 grams is placed in a 1.000 liter flask and...
chem sorry the last one did not have the question - A sample of PCl5 weighing 2....
CHEMISTRY - Equilibrium Equation with Partial Pressures PCl3(g) +Cl2(g) <...
chem - A sample of PCl5 weighing 2.69 grams is placed in a 1.000 liter flask and...
chemistry - Phosphorus trichloride gas and chlorine gas reacts to form ...
chemistry equilibriums - At a certain temperature, 2.00 moles of phosphorus(V) ...
Chemistry - An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has a partial...
chemistry - A reaction starts with 1.00 mol each of PCl3 and Cl2 in a 1.00-L ...
Chemistry - You wish to know the enthalpy change for the formation of liquid ...
For Further Reading