Posted by Kaili on Friday, March 9, 2012 at 7:59pm.
If you have Q you are half way home.
Q = 4.45E-3 = pH2*(Fe^2+)/(Fe)(H^+)^2
Substitute 1.00 for pH2, 0.001 for (Fe^2+), y for (H^+) and solve for x.
Then ...........HA ==> H^+ + A^-
initial.......1.00.....0.....0
change........-y.......y.....y
equil.......1.00-y......y.....y
Ka = (H^+)(A^-)/(HA)
You know (H^+) which is the x you solved for, you know HA and A^- = x also. Solve for Ka.
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