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April 24, 2014

Homework Help: Chemistry...please help

Posted by Kaili on Friday, March 9, 2012 at 7:59pm.

A galvanic cell is based on the following half-reactions:
Fe2+ + 2e- --> Fe(s) E= 0.440 V
2H+ + 2e- --> H2(g) E= 0.000 V
where the iron compartment contains an iron electrode and [Fe2+] = 1.00 x 10-3 M and the hydrogen compartment contains a platinum electrode, PH2 = 1.00 atm, and a weak acid HA at an initial concentration of 1.00 M. If the observed cell potential is 0.258 V at 25 degrees C, calculate the Ka value for the weak acid HA
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I calculated Q from the nernst equation and got 4.45 X 10^-3 but i go from here/how do i get the Ka from this

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