Posted by L.Bianchessi on Friday, March 9, 2012 at 7:45pm.
The point would be the intersection of y = 2x-1 with the perpendicular to that line passing through (2,-1)
slope of y = 2x-1 is 2
so the slope of the perpendicuar is -1/2
and the perpendicular is
y = (-1/2)x + b, with (2,-1) on it
so -1 = (-1/2)(2) + b
b =0
so intersect y = 2x-1 with y = (-1/2)x
2x - 1 = (-1/2)x
4x - 2 = -x
5x = 2
x = 2/5
then y = (-1/2)(2/5) = -1/5
the point is (2/5 , -1/5)
Related Questions
precalc - I;m not sure if i am doing this right...I keep getting a negative ...
Math - How do you: Find the shortest distance, to two decimal places from the ...
Calculus - Find the point on the graph of y = x^2 + 1 that’s closest to the...
Calculus - Find the point on the line 2x+7y-6=0 which is closest to the point (-...
Geometry - Okay, this is a problem that I've tried over ten times before ...
calculus - My teacher told me to use the distance formula for this problem but ...
calc - standard equation of circle concentric with X^2+Y^2-2X-8Y+1=0 and tangent...
Algebra II - If the distance from the point (5,k) to the line 8x - 15y + 8 + 0 ...
Precalc - At the point were a line intersects a plane [with the equation (24x+...
calculus - Consider line segments which are tangent to a point on the right half...
For Further Reading
