Sunday

September 21, 2014

September 21, 2014

Posted by **L.Bianchessi** on Friday, March 9, 2012 at 7:41pm.

I got Area=x(8-1/2x^2). Is that right?

And perimeter= x+16-x^2+ (square root 256-30x^2)

Did I do this question right?

- MaTH!!! -
**Reiny**, Friday, March 9, 2012 at 9:17pmYour area is correct

But for the perimeter, ....

let the hypotenuse by y

y^2 = x^2 + (16-x^2)^2

= x^2 + 256 - 32x^2 + x^4

y = √(256 - 31x^2 + x^4)

perimeter = x + √(256-31x^2+x^4) + 16- x^2

testing:

let P be (3, 7)

then AP = 7

OA = 3 and OP = √(9+49) = √58

Perimeter = 3 + 7 + √58 = 10+ √58

according to my formula

Perimeter = 3 + √(256 - 31(9) + 81) + 16 - 9

= 10 + √58

Well, how about that?

**Answer this Question**

**Related Questions**

calculus - A curve passes through the point (1,-11) and it's gradient at any ...

calculus - Consider line segments which are tangent to a point on the right half...

Calculus - With y=f(x) (2x-10)^1/2 having a virtual line joined at point Q from ...

Maths - a curve ahs parametric equations x=t^2 and y= 1-1/2t for t>0. i)find ...

math - A curve has implicit equation x^2-2xy+4y^2=12 a)find the expression for ...

Math-Calculus - Given point P(a,3) for a <0. Find point R, S,T,U that are ...

math - find the eqt. of tangent to the curve y=-x^2+2x-10 @ the point where the ...

Precalculus - The figure below shows a conchoid of Nicomedes. The top part is ...

Calculus - Consider line segments which are tangent to a point on the right ...

math - With regards to question J: The variables x and y are connected by the ...