Posted by April on Friday, March 9, 2012 at 4:06pm.
If CSC X = 4 in the quadrant 1, what is COS X?

Trig  john, Friday, March 9, 2012 at 4:41pm
cos(x)=(4^21^2)^(1/2). If your csc=4, then build your right triangle and if csc(x) is hyp/opposite, then you should get what i have put above. Hope this helps

Trig  Steve, Friday, March 9, 2012 at 5:02pm
if cscx = 4, sinx = 1/4
cos^2 = 1  sin^2 = 15/16
cosx = √15 / 4

Trig  john, Friday, March 9, 2012 at 6:53pm
my mistake, I forgot to put the 4 underneath the sq root of 15
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