Posted by April on .
If CSC X = 4 in the quadrant 1, what is COS X?

Trig 
john,
cos(x)=(4^21^2)^(1/2). If your csc=4, then build your right triangle and if csc(x) is hyp/opposite, then you should get what i have put above. Hope this helps

Trig 
Steve,
if cscx = 4, sinx = 1/4
cos^2 = 1  sin^2 = 15/16
cosx = √15 / 4 
Trig 
john,
my mistake, I forgot to put the 4 underneath the sq root of 15