Posted by Taeyeon on Friday, March 9, 2012 at 12:43pm.
need the intersection ....
3x = 4-x
4x=4
x = 1
height of revolved region = radius of rotation
= 4-x - 3x = 4 - 4x
area = ∫(4-4x) dx from 0 to 1
= [4x - 2x^2] from 0 to 1
= (4 - 2) - 0
= 2
volume = π∫ (4-4x) dx from 0 to 1
= π∫(16 - 32x + 16x^2) dx from 0 to 1
= π[16x - 16x^2 + (16/3)x^3 ] from 0 to 1
= π( 16 - 16 + 16/3 - 0)
= 16π/3
check my arithmetic
Related Questions
calculus - Which has more area, the region in the first quadrant enclosed by the...
Calculus - The region in the first quadrant enclosed by the graphs of y = x and ...
calculus - Consider the graphs of y = 3x + c and y^2 = 6x, where c is a real ...
Calculus - Let f(x)=x^3+3x and g(x=5x^2-x Determine the area of the region ...
calculus - Sketch the region in the first quadrant enclosed by the given curves...
calculus - Find the area of the region in the first quadrant enclosed by the ...
Calculus - Find the volume of the solid obtained by rotating the region enclosed...
calculus - 2. Sketch the region in the first quadrant that is bounded by the ...
calculus - Let A be the bounded region enclosed by the graphs of f(x) = x , g(x...
Calculus AB/AP - Use the rectangles with the given dimensions to approximate the...
For Further Reading
