Posted by Angelina on .
2x^3+3x^2-120x
to find the critical numbers I took the derivative which is 6x^2+6x-120 so divide by 6 to simplify
x^2+x-20=0
so the critical numbers will be (4,0) and (-5,0) but its wrong I don't know y?
Posted by Angelina on .
2x^3+3x^2-120x
to find the critical numbers I took the derivative which is 6x^2+6x-120 so divide by 6 to simplify
x^2+x-20=0
so the critical numbers will be (4,0) and (-5,0) but its wrong I don't know y?