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Posted by on Thursday, March 8, 2012 at 10:13pm.

If the time elapsed is 4.26 min, what is the value of the rate constant, k?

ln[R]t / [R]o = -0.0237

I am not sure how to slove this.

Would I do ln 4.26 minutes times -0.0237???

  • chemistry(?) - , Friday, March 9, 2012 at 1:21am

    How are you defining k?
    Are you taking the ln of [R] or of [R(t)]/R(0)] ?
    Is [R] the concentration of a reactant?

    This looks like an equation for first-order chemical decomposition or radioactive decay.

    If [R(t)] = [Ro]e^-kt, then
    ln{[R(t)]/R(0)]} = -kt
    If -kt = -0.0237 when t = 4.26 min, then
    k = 5.56*10^-3 min^-1

  • Math(Please answer just a quick question!!!!) - , Friday, March 9, 2012 at 6:56pm

    Ok how did you get 5.56e-3???

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