Homework Help: Math(Please help)

Posted by Hannah on Thursday, March 8, 2012 at 10:11pm.

ln [5.01E-3] = ln(4.86E-2) - (1.80E-2s-1)(t s) Solve for t.

t = 126 s

First I did 4.86e-2 - 1.80e-2 and then on my calculator I pressed the 2nd button and then ln and got 1.031. Then I did the same thing to get the ln of 5.01e-3 and divided that by 1.031 but did not get 126 as the answer. Where did I mess up?

Math - Steve, Thursday, March 8, 2012 at 5:31pm
Does the equation mean

ln(.00501) = ln(.0486) - (.0180s - 1)(ts)?

Doesn't look like that's what you were doing. Try reposting with plenty of parentheses for clarity.

Use ^ for power if needed as in s^(-1) for 1/s

yes thats what it means and how I posted it is exactly how it is written on my homework but I just cant seem to get that answer

Am I suppose to convert seconds into something else??

Math(Please help) - Steve, Friday, March 9, 2012 at 12:34pm
ln .0051 = −5.2963
ln .0486 = −3.0241
so now we have

-2.2722 = .0180t(s-s^2)
t = 126.233/(s-s^2)

Now, if the problem read

ln [5.01E-3] = ln(4.86E-2) - (1.80E-2/s)(t)

it would be a better fit.
I think your s-1 was really s^(-1)
Math(Please help) - Hannah, Friday, March 9, 2012 at 6:18pm
ok thank you so much!!!

Answer this Question

Related Questions

Math - ln [5.01E-3] = ln(4.86E-2) - (1.80E-2s-1)(t s) Solve for t. t = 126 s ...
Math differentiation - 1. y = x^x 2. y = (sin^2xtan^4x)/(x^2+1)^2 3. y = x^(1/x...
Math - What does the following infinite series starting at k=2 converge to: &...
Math - ln x^2(x+1)/x+2 Write in terms of ln(x), ln(x+1), and ln(x+2) is the ...
solving for x math - 2e^(4x^2)=3 how do i solve for x. do i use the ln methode ...
math - Express y as a function of x. C is a positive number. 3 ln y= 1/2ln (2x+1...
algebra - can someone plzs help me solve the equations by finding the exact ...
Math - Given the axioms: ln x = definite integral from 1 to x of 1/t dt ln e = 1...
Math - Find the derivative of: ln(2x/x+1) the answer is 1/x(x+1) but i can't...
pre cal - (1/3)LN27 + 2LNx = LN(2-x) i think i just need help getting started. I...

For Further Reading

First Name:
School Subject:
Answer: