Posted by **Anonymous** on Thursday, March 8, 2012 at 9:58pm.

A 9 V battery is connected in series with a 100 Ω resistor and 12µF capacitor. The capacitor is initially uncharged. What is the capacitive time constant of the circuit? How much charge q(t) is in the capacitor after two time constants?. What is the limiting value of the charge on the capacitor? When the battery is disconnected and the capacitor is discharged, what is the current i(t) in the circuit after two time constants? What is the limiting value of the current? Draw the curves q(t) and i(t) as functions of time and label them appropriately.

- physics -
**drwls**, Friday, March 9, 2012 at 12:44am
The time constant is RC and that the initial capacitor charge is q(0) = CV. That is basic stuff.

Show us what you know, look up and learn the equations, and don't expect us to do all the work here. You will learn the subject better that way.

## Answer This Question

## Related Questions

- Physics - Could someone please tell me what equations i am suppose to use to ...
- Physics - A circuit with a capacitor took .138s to discharge from its max charge...
- College Physics - A circuit consists of 3 components connected between 2 ...
- Physics - A circuit with a capacitor took .128s to discharge from its max charge...
- physics - A tunable capacitor (with variable capacitance) is charged by a U0=12 ...
- Physics - A tunable capacitor (with variable capacitance) is charged by a U0=12 ...
- heeeelp physics - A tunable capacitor (with variable capacitance) is charged by ...
- heeelp tooough physics - A tunable capacitor (with variable capacitance) is ...
- Physics - An RC-circuit has a time constant of 6x10-3 seconds. The capacitor ...
- Physics - Two circular metal disc each of 3.00 cm diamter are 1.5 mm apart make ...

More Related Questions