posted by HELP PLEASE on .
1) Calculate the molarity of a solution of sodium hydroxide, NaOH,if 23.64 mL of this solution is needed to neutralize 0.5632g of potassium hydrogen phthalate.
2) It is found that 24.68 mL of 0.1165M NaOH is needed to titrate 0.2931 g of an unknown acid to the phenolphthalein end point. Calculate the equivalent mass of the acid.
IS IT 0.1167 M ?????
0.1167 is right.
Use mL x N x milliequivalent weight = grams.
You have mL, M(same as normality in this case), and grams. Solve for milliequivalent weight, then multiply by 1000.
Be patient. All of us are volunteers and we get around as fast as we can.
I have the same thing. I dnt know the second one but the first I ended up getting. .1167mmoles/ml
hey guisee im a chem teeecher and i say ur probably right on that, as long as you take the variable Y into account, and then use the 5 percent rule. that will make hydrogen bonding possible, and return a value of .1167. :)