Homework Help: statistics

Posted by Gift on Thursday, March 8, 2012 at 5:46pm.

The time required by workers to complete an assembly job has a mean of 50 minutes and a standard deviation of 8 minutes. To spot check the workers' progress on a particular day, their supervisor intends to record the times 60 workers take to complete one assembly job apiece. What is the probability that the sample mean will be more than 52 minutes?

statistics - PsyDAG, Friday, March 9, 2012 at 6:39am
Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

Answer this Question

Related Questions

Statistics - 18 workers at a large assembly plant were asked the time it took to...
statistics - An employer wants to estimate to set a time limit so that 75% of ...
statistics - 18 workers at a large assembly plant were asked the time it took to...
stat - An employer wants to set a time limit so that 75% of the employees will ...
business statistics - For one of the tasks in a manufacturing process, the mean ...
Statistics - length of time in minutes required to complete exercises is ...
statistics - The times taken to complete a statistics test by all students are ...
statistics - The times taken to complete a statistics test by all students are ...
statistics - historically, the mean timr to complete this statistics test is 54 ...
statistics - the times required to assemble a product part are normally ...

For Further Reading

First Name:
School Subject:
Answer: