Math
posted by Rajit Rastogi .
A bag contains 5 balls,8 white balls, 9 green balls,7 blue balls& 6 yellow balls.A ball is drawn at random .Find the probablity that the ball in neither green nor red ?

What color are the five balls mentioned first? You must have left out a word. Probably "red" . If a ball in neither green nor red, it must be white, yellow or blue. That probability is 21/35 = 3/5 = 60%

A bag contains 5 balls,8 white balls, 9 green balls,7 blue balls& 6 yellow balls.A ball is drawn at random .Find the probablity that the ball in neither green nor red ?
please let me know the formula also 
You still have stated the problem incorrectly. You omitted the color of the first five balls. I have already answered what I the assume is the question