Posted by simon on Thursday, March 8, 2012 at 2:51am.
Let x and y be the two speeds, x>y.
First part:
after 3 hours of driving towards each other, the distance is reduced from 230 to 20, so
3(x+y)=230-20
x+y=70
Speed of one is 10 km less than the other:
x-y=10
We have a sum and difference problem where the solution is
x=(sum+difference)/2=40
y=(sum=difference)/2=30
pot it.
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