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August 1, 2014

August 1, 2014

Posted by **simon** on Thursday, March 8, 2012 at 2:51am.

- math -
**MathMate**, Thursday, March 8, 2012 at 9:41amLet x and y be the two speeds, x>y.

First part:

after 3 hours of driving towards each other, the distance is reduced from 230 to 20, so

3(x+y)=230-20

x+y=70

Speed of one is 10 km less than the other:

x-y=10

We have a sum and difference problem where the solution is

x=(sum+difference)/2=40

y=(sum=difference)/2=30

- math -
**Henry**, Friday, March 9, 2012 at 9:17ampot it.

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