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October 23, 2014

October 23, 2014

Posted by **Anonymous** on Wednesday, March 7, 2012 at 11:25pm.

Let z = ∫e^(sin(t))dt from x to y

a = x

b = y

I tried thinking about it like a chain rule but even then i'm a little unsure.

I know dz/dt = e^(sin(t)). Can you please point me in the right direction if i'm supposed to use the chain rule.

- calculus -
**Steve**, Thursday, March 8, 2012 at 12:11pmif F = Integral(f(t)) [x,y] then

dF/dx = f(x) = e^sin(x)

dF/dy = -f(y) = -e^sin(y)

wikipedia has a good article on differentiation under the integral

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