Wednesday

July 23, 2014

July 23, 2014

Posted by **Anonymous** on Wednesday, March 7, 2012 at 11:25pm.

Let z = ∫e^(sin(t))dt from x to y

a = x

b = y

I tried thinking about it like a chain rule but even then i'm a little unsure.

I know dz/dt = e^(sin(t)). Can you please point me in the right direction if i'm supposed to use the chain rule.

- calculus -
**Steve**, Thursday, March 8, 2012 at 12:11pmif F = Integral(f(t)) [x,y] then

dF/dx = f(x) = e^sin(x)

dF/dy = -f(y) = -e^sin(y)

wikipedia has a good article on differentiation under the integral

**Related Questions**

calculus - Let z = ∫e^(sin(t))dt from x to y a = x b = y I tried thinking ...

calculus - Let z = ∫e^(sin(t))dt from x to y a = x b = y I tried thinking ...

calculus - Let z = ∫(e^sin(t)dt) from x to y a = x b = y I tried thinking ...

calculus II - ∫ tan^2 x sec^3 x dx If the power of the secant n is odd, ...

Calc - How do you solve ∫sin(3x+4)dx? I got the -cos(3x+4) part, but do ...

Calculus - How do I use the chain rule to find the derivative of square root(1-x...

Calculus - Hello, I just wanted to verify if my work was good. Calculate the ...

Calculus AP - Use the table of integrals to find int cos^4 3x dx I found the ...

calculus - how do not understand how to find a deriviative of this function?Do i...

calculus - how do not understand how to find a deriviative of this function?Do i...