Posted by Mariah on Wednesday, March 7, 2012 at 11:20pm.
B. The total energy is reduced by
deltaE = 6.0m*g*0.500kg = 29.4 joules at the top of the trajectory
The missing energy goes to doing work against friction, equal to F*34 m = 29.4 J
Therefore F = 29.4J/34m = 0.865 N
(assuming F is constant). If not constant, F is the average force
Okay thank you!!
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