Posted by John on Wednesday, March 7, 2012 at 9:21pm.
Given the following hypothetical equations,
2A + B → 3C + 2D ΔH = 46.7kJ
C → B ΔH = 13.1kJ
2E → B ΔH = 84.5kJ,
what is the enthalpy change (kJ) for the following reaction?
A → D + 2E

Chemistry  DrBob222, Wednesday, March 7, 2012 at 9:45pm
Add eqn 1 as is to 3x eqn 2 to 2x the reverse of eqn 3. That will give you 2x the equn you want so take 1/2 of the final equation. When reversing an equation, change the sign of dH. When multiplying an equation, multiply dH by the same number. Add all of them take 1/2 final equation and 1/2 final dH.
Answer This Question
Related Questions
 AP Chemistry  Calculate ΔHrxn for the following reaction: C(s)+H2O(g)&#...
 chemistry  Calculate the enthalpy change, ΔrH, for the following reaction...
 Chemistry  Please help me! I don't know how to do this at all. Calculate the ...
 Chemistry  Calculate the enthalpy change, ΔrH, for the following reaction...
 Chemistry  Calculate the enthalpy change for the reactions NO(g) + O(g) →...
 Chemistry  Enthalpy Change Given the following reactions: S(s) + O2(g) → ...
 Chemistry  Calculate ΔHrxn for the following reaction: CaO(s)+CO2(g)→...
 chemistry  Given the following reactions Fe2O3(s) + 3CO (s) → 2Fe (s) + ...
 Chemistry  ou are given the following data. S(s) + 3/2 O2(g) → SO3(g) &#...
 Chemistry  Hydrogen cyanide is a highly poisonous, volatile liquid. It can be ...
More Related Questions