Given the following hypothetical equations,
2A + B → 3C + 2D ΔH = -46.7kJ
C → B ΔH = 13.1kJ
2E → B ΔH = 84.5kJ,
what is the enthalpy change (kJ) for the following reaction?
A → D + 2E
2A + B → 3C + 2D ΔH = -46.7kJ
C → B ΔH = 13.1kJ
2E → B ΔH = 84.5kJ,
what is the enthalpy change (kJ) for the following reaction?
A → D + 2E