Friday

November 28, 2014

November 28, 2014

Posted by **John** on Wednesday, March 7, 2012 at 9:21pm.

2A + B → 3C + 2D ΔH = -46.7kJ

C → B ΔH = 13.1kJ

2E → B ΔH = 84.5kJ,

what is the enthalpy change (kJ) for the following reaction?

A → D + 2E

- Chemistry -
**DrBob222**, Wednesday, March 7, 2012 at 9:45pmAdd eqn 1 as is to 3x eqn 2 to 2x the reverse of eqn 3. That will give you 2x the equn you want so take 1/2 of the final equation. When reversing an equation, change the sign of dH. When multiplying an equation, multiply dH by the same number. Add all of them take 1/2 final equation and 1/2 final dH.

**Answer this Question**

**Related Questions**

chemistry - Calculate the enthalpy change, ΔrH, for the following reaction...

Chemistry - Calculate the enthalpy change, ΔrH, for the following reaction...

Chemistry - Calculate the enthalpy change for the reactions NO(g) + O(g) →...

Chem - Set up a Hess’s law cycle, and use the following information to calculate...

Chemistry - ou are given the following data. S(s) + 3/2 O2(g) → SO3(g) &#...

Chemistry - From the following data at 25°C, H2(g) + Cl2(g) → 2HCl(g) &#...

chemistry - Use the standard reaction enthalpies given below to determine Δ...

Chemistry - Hydrogen cyanide is a highly poisonous, volatile liquid. It can be ...

chemistry - Hydrogen cyanide is a highly poisonous, volatile liquid. It can be ...

Chemistry - How do i calculate: What is is ΔG° at 25 °C? 2O3(g) → 3 ...