Posted by **Anonymous** on Wednesday, March 7, 2012 at 8:39pm.

Let z = ∫e^(sin(t))dt from x to y

a = x

b = y

I tried thinking about it like a chain rule but even then i'm a little unsure.

I know dz/dt = e^(sin(t)). Can you please point me in the right direction if i'm supposed to use the chain rule.

## Answer this Question

## Related Questions

- calculus - Let z = ∫e^(sin(t))dt from x to y a = x b = y I tried thinking ...
- calculus - Let z = ∫(e^sin(t)dt) from x to y a = x b = y I tried thinking ...
- calculus - Find dz/dy and dz/dx Let z = ∫e^(sin(t))dt from x to y a = x b...
- calculus II - ∫ tan^2 x sec^3 x dx If the power of the secant n is odd, ...
- Math integrals - What is the indefinite integral of ∫ [sin (π/x)]/ x^...
- calculus - Suppose R is the rectangle 1<=x<=4, |y|<=2 and evaluate the ...
- Calc - How do you solve ∫sin(3x+4)dx? I got the -cos(3x+4) part, but do ...
- Calculus - Hello, I just wanted to verify if my work was good. Calculate the ...
- Calculus 2 Trigonometric Substitution - I'm working this problem: ∫ [1-tan...
- Calculus - I have y = sin^2(3^(x)) which I rewrite as y = (sin(3^(x)))^2 I got ...