Determine the molarity of a sodium hydroxide solution? if 37.34 mL of it are required to neutralize 1.922 g of citric acid.
balanced equation- 3NaOH(aq)+H3C6H5O7-->3H2O(l)+NaC6H5O7(aq…
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You made a typo in the equation. It should be Na3C6H5O7(aq) on the right.
moles citric acid = grams/molar mass
Convert moles citric acid to moles NaOH. From the equation you can see that 3 moles NaOH = 1 mol citric acid; therefore, mols NaOH = 3 x moles citric acid.
Then M NaOH = moles NaOH/L NaOH
To determine the molarity of a sodium hydroxide solution (NaOH), we can use the equation provided to calculate the amount of NaOH used in the reaction. We will then use this information to calculate the molarity.
Step 1: Calculate the number of moles of citric acid (H3C6H5O7) used.
We are given the mass of citric acid, 1.922 g. To calculate the number of moles, we need to divide the mass by the molar mass of citric acid.
The molar mass of citric acid (H3C6H5O7) can be determined from the periodic table:
H: 1 g/mol x 3 = 3 g/mol
C: 12 g/mol x 6 = 72 g/mol
O: 16 g/mol x 7 = 112 g/mol
Total molar mass = 3 g/mol + 72 g/mol + 112 g/mol = 187 g/mol
Number of moles of citric acid = 1.922 g / 187 g/mol = 0.0103 mol
Step 2: Use the balanced equation to determine the mole ratio between NaOH and citric acid.
From the balanced equation, we can see that 3 moles of NaOH react with 1 mole of citric acid (H3C6H5O7).
Step 3: Calculate the number of moles of NaOH used.
Using the mole ratio from step 2, we can calculate the number of moles of NaOH used in the reaction:
Number of moles of NaOH = 0.0103 mol x (3 mol NaOH / 1 mol citric acid) = 0.0309 mol NaOH
Step 4: Calculate the volume of the NaOH solution.
We are given the volume of the NaOH solution, 37.34 mL. However, to use this volume to calculate molarity, we need to convert it to liters:
Volume of NaOH solution = 37.34 mL = 37.34 mL x (1 L/1000 mL) = 0.03734 L
Step 5: Calculate the molarity of the NaOH solution.
Molarity (M) is defined as moles of solute divided by liters of solution.
Molarity of NaOH = Number of moles of NaOH / Volume of NaOH solution
Molarity of NaOH = 0.0309 mol / 0.03734 L = 0.828 M
Therefore, the molarity of the sodium hydroxide solution is 0.828 M.
To determine the molarity of a sodium hydroxide (NaOH) solution, we need to use the balanced chemical equation and the given data.
Given:
- Volume of NaOH solution: 37.34 mL
- Mass of citric acid (H3C6H5O7): 1.922 g
Step 1: Convert the volume of NaOH solution to liters.
Since molarity is defined as the number of moles of solute per liter of solution, we need to convert the given volume from milliliters to liters.
37.34 mL * (1 L / 1000 mL) = 0.03734 L
Step 2: Calculate the molar mass of citric acid (H3C6H5O7).
The molar mass of citric acid can be found by summing up the atomic masses of its constituent elements.
H (hydrogen) has an atomic mass of 1.01 g/mol, C (carbon) has an atomic mass of 12.01 g/mol, and O (oxygen) has an atomic mass of 16.00 g/mol.
3(1.01 g/mol) + 6(12.01 g/mol) + 7(16.00 g/mol) = 192.13 g/mol
Step 3: Convert the mass of citric acid to moles.
Using the molar mass of citric acid calculated in Step 2, we can convert the given mass from grams to moles.
1.922 g * (1 mol / 192.13 g) = 0.009997 mol (rounded to 4 decimal places)
Step 4: Determine the stoichiometric ratio between NaOH and citric acid.
From the balanced chemical equation:
3NaOH(aq) + H3C6H5O7 --> 3H2O(l) + NaC6H5O7(aq)
We can see that 3 moles of NaOH are required to react with 1 mole of citric acid.
Step 5: Calculate the number of moles of NaOH.
Using the stoichiometric ratio determined in Step 4, we can calculate the number of moles of NaOH.
0.009997 mol * (3 mol NaOH / 1 mol citric acid) = 0.02999 mol (rounded to 5 decimal places)
Step 6: Calculate the molarity of the NaOH solution.
Finally, we can calculate the molarity of the NaOH solution by dividing the moles of NaOH by the volume of the solution in liters.
Molarity (M) = Moles of solute / Volume of solution (in liters)
Molarity = 0.02999 mol / 0.03734 L
Molarity ≈ 0.803 M (rounded to 3 decimal places)
Therefore, the molarity of the sodium hydroxide solution is approximately 0.803 M.