Sunday
May 19, 2013

# Homework Help: calculus

Posted by John on Wednesday, March 7, 2012 at 11:32am.

If 0 degrees < x < 180 degrees, what values of x, to the nearest degree, are the solution to the equation
2tan to the square x + 5tanx - 12 = 0

• calculus - Steve, Wednesday, March 7, 2012 at 12:46pm

2tan^2(x) + 5tan(x) - 12 = 0
(tanx+4)(2tanx-3) = 0

tanx = -4 or 1.5

you should be able to take it from there . . .

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