If 0 degrees < x < 180 degrees, what values of x, to the nearest degree, are the solution to the equation
2tan to the square x + 5tanx - 12 = 0
2tan^2(x) + 5tan(x) - 12 = 0
(tanx+4)(2tanx-3) = 0
tanx = -4 or 1.5
you should be able to take it from there . . .