CAlculus
posted by Erikan Attah on .
using chain rule find the derivative of y=xsin1/x

y' = sin(1/x) dx/dx + x d(sin(1/x))/dx
= sin (1/x)+ x cos(1/x)d(1/x)/dx
= sin (1/x)+ x cos(1/x)(1/x^2)
= sin(1/x)  (1/x)cos(1/x)
posted by Erikan Attah on .
using chain rule find the derivative of y=xsin1/x
y' = sin(1/x) dx/dx + x d(sin(1/x))/dx
= sin (1/x)+ x cos(1/x)d(1/x)/dx
= sin (1/x)+ x cos(1/x)(1/x^2)
= sin(1/x)  (1/x)cos(1/x)