Homework Help: maths

Posted by festus on Wednesday, March 7, 2012 at 3:46am.

the sum of the 4th and 6th terms of an A.P is 42. the sum of the 3rd and 9th terms of the progression is 52. find the first term, the common difference and the sum of the first ten terms of the progression.

maths - Steve, Wednesday, March 7, 2012 at 12:25pm
what don't you get?

T4 = a+3d
T6 = a+5d
a+3d + a+5d = 42
2a + 8d = 42
a+4d = 21

T3 = a+2d
T9=a+8d
a+2d + a+8d = 52
2a + 10d = 52
a+5d = 26

a+4d = 21
a+5d = 26
d = 5
so a=1

sum of T1-T10 = 10/2(1+46) = 235

AP = 1 6 11 16 21 26 31 36 41 46 . . .
maths - Terfa sakaa, Sunday, October 14, 2012 at 4:16am
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