Posted by **george** on Wednesday, March 7, 2012 at 12:33am.

A 0.180 kg baseball, traveling 32.0 m/s, strikes the catcher's mitt, which recoils 13.0 cm in bringing the ball to rest. What was the average force (in newtons) applied by the ball to the mitt?

- physics -
**drwls**, Wednesday, March 7, 2012 at 12:59am
Kinetic energy loss equals work done pushing the mitt. Therefore,

Force = MV^2/(2X)

- physics -
**Anonymous**, Wednesday, March 7, 2012 at 1:35am
I was just wondering if you just square v and also what do you put in for x?

- physics -
**drwls**, Wednesday, March 7, 2012 at 1:56am
yes, V gets squared. X = 0.13 m

The force will be in Newtons.

## Answer this Question

## Related Questions

- physics - A 0.110 kg baseball, traveling 32.0 m/s, strikes the catcher's mitt, ...
- Physics - A 0.130 kg baseball, traveling 35.0 m/s, strikes the catcher's mitt, ...
- Physics - A 0.130 kg baseball, traveling 35.0 m/s, strikes the catcher's mitt, ...
- Physics - A 0.133 kg baseball traveling 30.6 m/s strikes the catcher's mitt, ...
- Physics 6A - A 0.140- baseball traveling 34.0 strikes the catcher's mitt, which...
- Physical - A 0.140-kg baseball traveling 38.0m/s strikes the catcher's mitt, ...
- Physics - A 0.140-kg baseball traveling 39.0 m/s strikes the catcher's mitt, ...
- Physics - A 0.145-kg baseball traveling 35.0 m/s strikes the catcher's mitt ...
- Physics - A 0.140 kg baseball traveling 39.0 m/s strikes the catchers mitt, ...
- Physics - A 0.140 kg baseball traveling 39.0 m/s strikes the catchers mitt, ...

More Related Questions