Thursday
March 23, 2017

Post a New Question

Posted by on Wednesday, March 7, 2012 at 12:27am.

A 8.0 kg object, moving with a constant velocity of 8.0 m/s, is acted upon by a force of 14 N in the direction of the motion for 6.0 s. What is the velocity (in meters/second) of the object at the end of this time?

  • physics - , Wednesday, March 7, 2012 at 1:08am

    The impulse applied by the force is 14*6 = 84 kg*m/s

    The initial momentum of 64 kg*m/s will increase to 64 + 84 = 148 kg*m/s, and the new velocity will be 148/8 = 18.5 m/s

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question