A 8.0 kg object, moving with a constant velocity of 8.0 m/s, is acted upon by a force of 14 N in the direction of the motion for 6.0 s. What is the velocity (in meters/second) of the object at the end of this time?
The impulse applied by the force is 14*6 = 84 kg*m/s
The initial momentum of 64 kg*m/s will increase to 64 + 84 = 148 kg*m/s, and the new velocity will be 148/8 = 18.5 m/s
To determine the velocity of the object at the end of the given time, you need to consider the net force acting on the object using Newton's second law of motion.
Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. Since the object is moving with a constant velocity, its acceleration is zero, and the net force acting on it is also zero.
In this case, a force of 14 N is acting on an 8.0 kg object in the direction of motion. We can determine the acceleration by using the formula:
F = m * a
Where F is the force, m is the mass, and a is the acceleration.
Rearranging the formula:
a = F / m
Substituting the given values:
a = 14 N / 8.0 kg
a ≈ 1.75 m/s²
Since the acceleration is zero, with a constant velocity of 8.0 m/s, the velocity of the object at the end of the given time of 6.0 seconds will remain the same:
Velocity = 8.0 m/s
Thus, the velocity of the object at the end of the given time is 8.0 m/s.