Posted by Leanna on Tuesday, March 6, 2012 at 11:04pm.
P(0)=Ce^(k*0)=C
P(1)=Ce^(k*1)=Ce^k
P(1)/P(0)=2=(ce^k)/C=e^k
Take natural log
ln(2)=ln(e^k)=k
k=ln(2)=0.6931 approx.
Related Questions
maths --plse help me.. - A bacteria culture has an initial population of 600. ...
maths - The variation in size from year to year of a particular population can ...
maths - The variation in size from year to year of a particular population can ...
maths - The variation in size from year to year of a particular population can ...
SCI 275 - The Population Size explain the four factors that produce changes in ...
Population Size - 200- to 300-word response to the following: Explain the four ...
population size checkpoint - Post a 200- to 300-word response to the following: ...
Population size Checkpoint - Post a 200- to 300-word response to the following: ...
calculus - The number N of bacteria in a culture is given by the model N=250e^kt...
Precalc - The number N of bacteria in a culture is given by the model N=250e^kt ...
For Further Reading