Posted by jessica on Tuesday, March 6, 2012 at 11:03pm.
a) A' = dA/dt = -100*(1.6^-t)*ln1.6
= -47*1.6^-t
b) When A(t) = (1/2)A(0),
100*1.6^-t = 50
1.6^-t = 0.5
-t ln1.6 = ln0.5
t = 1.475
c) A' at t = 1.475 is half the rate at t = 0, or -23.5
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