Posted by DCM on .
An object is placed in front of a converging lens in such a position that the lens (f = 14.0 cm) creates a real image located 27.0 cm from the lens. Then, with the object remaining in place, the lens is replaced with another converging lens (f = 18.0 cm). A new, real image is formed. What is the image distance of this new image?
I will be happy to check your optics equation work