Posted by **jim** on Tuesday, March 6, 2012 at 6:13pm.

The value of g at Earth’s surface is about 9.8 m/s^2. If Earth were of uniform density (same mass/volume throughout), what would the value of g be inside Earth at half its radius?

- physics -
**drwls**, Tuesday, March 6, 2012 at 7:16pm
g'(r) = G* m(r)/r^2, where m is the mass within radius r.

G is the universal constant of gravity

At r = R/2, 1/8 of the earth's total mass is inside. Call the value of g there g'.

g'(at r = R/2) = G*(M/8)/(R/2)^2

= (1/2)G*M/R^2

= g/2 = 4.9 m/s^2

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